(x+(5/2))^2=(7/4)

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Solution for (x+(5/2))^2=(7/4) equation: 


x in (-oo:+oo)

(x+5/2)^2 = 7/4 // - 7/4

(x+5/2)^2-(7/4) = 0

(x+5/2)^2-7/4 = 0

(4*(x+5/2)^2)/4-7/4 = 0

4*(x+5/2)^2-7 = 0

4*x^2+20*x+18 = 0

4*x^2+20*x+18 = 0

2*(2*x^2+10*x+9) = 0

2*x^2+10*x+9 = 0

DELTA = 10^2-(2*4*9)

DELTA = 28

DELTA > 0

x = (28^(1/2)-10)/(2*2) or x = (-28^(1/2)-10)/(2*2)

x = (2*7^(1/2)-10)/4 or x = (-2*7^(1/2)-10)/4

2*(x-((-2*7^(1/2)-10)/4))*(x-((2*7^(1/2)-10)/4)) = 0

(2*(x-((-2*7^(1/2)-10)/4))*(x-((2*7^(1/2)-10)/4)))/4 = 0

(2*(x-((-2*7^(1/2)-10)/4))*(x-((2*7^(1/2)-10)/4)))/4 = 0 // * 4

2*(x-((-2*7^(1/2)-10)/4))*(x-((2*7^(1/2)-10)/4)) = 0

( x-((-2*7^(1/2)-10)/4) )

x-((-2*7^(1/2)-10)/4) = 0 // + (-2*7^(1/2)-10)/4

x = (-2*7^(1/2)-10)/4

( x-((2*7^(1/2)-10)/4) )

x-((2*7^(1/2)-10)/4) = 0 // + (2*7^(1/2)-10)/4

x = (2*7^(1/2)-10)/4

x in { (-2*7^(1/2)-10)/4, (2*7^(1/2)-10)/4 }

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